First check that the crate starts at rest. Static friction can balance a push up to the stated maximum, including equality in this ideal model. It points opposite the attempted slide. A leftward push needs rightward balancing friction, not an automatic leftward force.
Worked example
A different crate has a static limit of 16 N. A 10 N push left is balanced by 10 N of friction right, so the net horizontal force is 0 N. The unused 6 N of possible friction is not another force.
Further inquiry
Use a new static limit of 20 N. Draw separate leftward-push trials below, at and above that limit. Identify the balancing force where rest is possible and explain what is unknown once sliding begins.
Review criteria
- State that each trial starts at rest and only two horizontal forces act.
- Use equal rightward friction below or at the limit, not always 20 N.
- Above the limit, do not invent a sliding-friction value.