In these trials sliding friction is 6 N left. Use that value while the box slides right, then subtract opposing forces. Net force right speeds this rightward slide up; net force left slows it. Zero net force keeps velocity unchanged.
Worked example
In a different example, an already-sliding box has push 8 N right and sliding friction 3 N left. Net force is 5 N right. If the push were instead 3 N right, it would keep the same velocity. These are horizontal forces only.
Further inquiry
Draw a new already-sliding-right trial with sliding friction 4 N left. Choose a push that speeds it up, one that keeps velocity unchanged, and one that slows it. Label force direction separately from motion direction.
Review criteria
- State that the box is already sliding right.
- Choose pushes above, equal to, and below 4 N and calculate each net force.
- Explain why a leftward net force first slows a rightward slide rather than immediately reversing it.