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Expand each bracket and combine like terms. If a nonzero coefficient of x remains, solve for one value. If x cancels, a true numerical statement means all real numbers here; a false statement means no solution. Never divide by zero.
Worked example
3(x - 2) = 3x + 1 reduces to -6 = 1, so there is no solution. But 3(x - 2) = 3x - 6 reduces to -6 = -6, so every real number works. Changing one constant changes the conclusion.