Count Fraction-Sized Loads - Practice 2

Keep the roll fixed while counting full and partial fraction-sized loads.

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Watch the lesson | Try Fraction Dock: choose Grouping

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Rename the available amount and the positive load size using a common piece size. Divide available pieces by pieces per load. Include partial loads: a leftover fraction of a roll must be compared with ONE load. This also works for loads larger than one roll. Check: number of loads x load size = available amount. Never divide by zero.

Worked example

7/6 divided by 2/3 = 7/4 loads. A load is 2/3 = 4/6, so seven sixth-size pieces make one four-piece load and 3/4 of another. The remaining three pieces are 3/6 of a roll but 3/4 of a LOAD. Check: 7/4 x 2/3 = 7/6. The diagram shows this example, not the questions.

Two equal whole-roll frames each have six equal pieces. Seven pieces are available. One load requires four sixths, or two thirds. Group 1 has four pieces; group 2 has three pieces and crosses the roll boundary. Seven sixths divided by two thirds is seven fourths of a load: one full load and three quarters of another. Practice questions use different amounts. — Matching numbers belong to the same load, including across roll frames. Each roll has six equal parts; one load needs four.

Would you believe it?

Changing the unit can change the count without changing the amount: one whole contains two halves or four quarters. Division counts the groups named by its divisor. Check by multiplying the group count by the group size.

OpenStax: dividing fractions

Question 1 7/8 divided by 1/4 = ? 7/32 7/2 3

Question 2 3/5 divided by 9/10 = ? 2/3 27/50 3/2

Question 3 4/9 divided by 4/9 = ? 0 16/81 1

Question 4 5/6 divided by 5/4 = __/3. What numerator fills the blank? Answer

Question 5 A positive amount is divided by a load size greater than 1 whole. Compared with the number naming the original amount, the quotient is: Always larger Always unchanged Smaller

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