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Reynolds number Re = rho v L / mu compares inertial and viscous effects using dynamic viscosity mu. Similar shape does not ensure similar flow: matching Re and other relevant parameters matters. A universal transition value for every shape does not exist.
Worked example
For rho = 1.2 kg/m^3, v = 10 m/s, L = 0.1 m and mu = 0.000018 Pa s, Re is about 66667. Halving L at the same speed halves Re. Doubling speed restores that Re if the fluid properties stay fixed.