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Falling Speeds: Average Versus Final Speed

Use distance totals to distinguish an interval average from a momentary speed.

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With rest start, no air and constant g = 10 m/s^2, distance fallen is y = gt^2/2 and final speed is v = gt. At two seconds, distance is 20 m and average speed over the interval is 10 m/s.

Worked example

The first second contributes 5 m. The next contributes 20 - 5 = 15 m. Equal time intervals have unequal distances because speed is increasing.

With no air and constant g of 10 meters per second squared, an object released from rest falls 5 meters in its first second and 15 more meters in its second second. Total distance is 20 meters.
With no air and constant g of 10 meters per second squared, an object released from rest falls 5 meters in its first second and 15 more meters in its second second. Total distance is 20 meters.
Question 1 How far has the object fallen after 2 s?
Question 2 What is the average speed over those 2 s?
Question 3 How far does it fall during the second second only?
Question 4 Why is final speed larger than the average here?
Question 5 For the same model, how far during the third second only?