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Math / Geometry / Grade 10 / mgact

Use Differences to Find Distance - Practice 2

The differences in x and y are perpendicular legs of a right triangle.

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The differences in x and y are perpendicular legs of a right triangle. Square both differences, add and take the nonnegative square root.

Worked example

From (1, 2) to (4, 6), differences are 3 and 4. Distance is the square root of 25, or 5.

From (1, 2) to (4, 6), differences are 3 and 4. Distance is the square root of 25, or 5.
Worked model: From (1, 2) to (4, 6), differences are 3 and 4. Distance is the square root of 25, or 5.
Question 1 Find the distance from (2, -1) to (20, 23) in coordinate units.
Question 2 Find the distance from (2, -1) to (23, 27) in coordinate units.
Question 3 Find the distance from (2, -1) to (26, 31) in coordinate units.
Question 4 Find the distance from (2, -1) to (29, 35) in coordinate units.
Question 5 Find the distance from (2, -1) to (32, 39) in coordinate units.