Prerequisites
Nonlinear differential equations, nondimensionalization, hyperbolic functions and asymptotic analysis.
With downward v >= 0, constant k, m, g, still fluid and no buoyancy, m dv/dt = mg - k v^2. Define vT = sqrt(mg/k), s = gt/vT and w = v/vT. From rest, dw/ds = 1 - w^2 and w = tanh(s). Displacement is y = (vT^2/g) ln(cosh(s)), measured downward from release.
Worked example
For m = 2 kg, g = 10 m/s^2 and k = 0.2 kg/m, vT = 10 m/s and s = t/(1 s). At s = 1, v/vT = tanh(1), about 0.762. Coefficients and buoyancy cannot silently change during the calculation.
Further inquiry
Derive the dimensionless equation and its rest-start solution. Obtain displacement by integrating velocity, then recover the short-time free-fall limit. Linearize near w = 1 to find the decay rate of a small speed deficit. Discuss why varying density, drag regime or buoyancy requires revising the model.
Review criteria
- Carry sign, coefficient and initial-condition assumptions through the derivation.
- Show both short-time and terminal-limit checks, including the deficit decay rate.
- Distinguish the constant-coefficient result from a realistic atmospheric descent.